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11h^2-7h-4=0
a = 11; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·11·(-4)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*11}=\frac{-8}{22} =-4/11 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*11}=\frac{22}{22} =1 $
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